[Resolved] Get parametric search values to find text WITHIN, not EQUAL TO a custom field 2

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[simonF-5]

FAO: Minesh (https://toolset.com/forums/users/minesh/)

Hi Minesh,
Thank you for your help with the parametric search. Your solution works for the 'Recommended Use' values, but not for the 'Difficulty' ones. I tried to copy the same filter substituting wpcf-difficulty for wpcf-use, but all I got was a 500 Internal Server Error on page reload. How do I go about making it work there?

[Minesh Supporter Languages: English (English ) Timezone: Asia/Kolkata (GMT+05:30)]

Hello. Thank you for contacting the Toolset support.

I've changed the code so your difficulty field also get counted with your search. Please find following modified code and I hope this will resolve your issue. I've already added this code to your functions.php file.

add_filter( 'wpv_filter_query', 'custom_search_criteria',10,2 );
function custom_search_criteria( $query_args ,$view_settings ) {
if (isset($view_settings['view_id']) && $view_settings['view_id'] == 1283 ) {
	
	foreach((array)$query_args['meta_query'] as $k=>$v):
            if(isset($v['key']) and ($v['key']=='wpcf-use' or $v['key']=='wpcf-difficulty')){
						
				$values = explode(",",$v['value']);
				if(count($values) > 1){
					$key = $v['key'];
					unset($query_args['meta_query'][$k]);
					
					foreach($values as $x=>$y):
						//$query_args['meta_query'][$k][$x]['key'] = 'wpcf-use';
						$query_args['meta_query'][$k][$x]['key'] = $key;
						$query_args['meta_query'][$k][$x]['type'] = 'CHAR';
						$query_args['meta_query'][$k][$x]['compare'] = 'LIKE';
						$query_args['meta_query'][$k][$x]['value'] = $y;
					endforeach;
					$query_args['meta_query'][$k]['relation'] = 'OR';
				}
			}
        endforeach;
}
return $query_args;
}

[simonF-5]

Thank you again Minesh, this works fantastically!
Best,
Simon