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[Resolved] conditional display based on url parameter

This support ticket is created 3 years, 8 months ago. There's a good chance that you are reading advice that it now obsolete.

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This topic contains 2 replies, has 2 voices.

Last updated by yosukeS 3 years, 8 months ago.

Assisted by: Waqar.

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#2026875

Tell us what you are trying to do?

I am trying to display a form ONLY WHEN url contains certain parameter such as &step=2
how do i do it?

Is there any documentation that you are following?
https://toolset.com/documentation/programmer-reference/views/views-shortcodes/#wpv-conditional

What is the link to your site?
hidden link

#2026993

Hi,

Thank you for contacting us and I'd be happy to assist.

To show the form, only when a specific URL parameter value is available in the URL, you can use the conditional shortcode along with the "wpv-search-term" shortcode:
https://toolset.com/documentation/legacy-features/views-plugin/using-shortcodes-in-conditions/
https://toolset.com/documentation/programmer-reference/views/views-shortcodes/#wpv-search-term

Example:


[wpv-conditional if="( '[wpv-search-term param="step"]' eq '2' )"] 
[cred_form form="form-to-add-new-post"]
[/wpv-conditional]

This will show the form with slug "form-to-add-new-post", only when "step=2" is set in the URL.

regards,
Waqar

#2027959

Thank you Wagar!
I thought the same code but somehow mine wasn't working. Your precise explanation and clear direction helped me to solve my issue.

Thank you so much!