[Resolved] How to insert a variable ?

[Author]

Posts

[Guillaume]

Hello hello

Here is the code to display a view in a php file :
$args = array(
'id' => '1111',
'limit' => '3'
);
echo render_view( $args )

If, instead of a static element, for the limit number I want to use a viariable. How can I use it ?

For exemple in another example my filter is "Brand" and I want to use the term of my taxonomy archives for exemple "Adidas". I have this code to display the term in my archive.php page : <?php $taxonomy = get_queried_object(); echo $taxonomy->name; ?>

How can I insert this code into the $args code ?

Thanks

[Guillaume]

I found the answer :

I need to replace 'limit' => '3'

by 'limit' => "$taxonomy->name"