How to display wpv-conditional with multiple apostrophes?

This support ticket is created 4 years, 2 months ago. There's a good chance that you are reading advice that it now obsolete.

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Supporter timezone: America/Jamaica (GMT-05:00)

Tagged: Views plugin

This topic contains 2 replies, has 2 voices.

Last updated by Peter 4 years, 2 months ago.

Assisted by: Shane.

Author

Posts

February 13, 2020 at 10:37 am #1506795

Peter

Tell us what you are trying to do?
I want to set a condition:
[wpv-conditional if="( '[wpv-post-taxonomy type="category" format="slug"]' ne '' )"]

The condition is a little bit complex, so I have to use multiple apostrophes in it. It is breaking the code, so the front-end is also broken. How can I display this shortcode without syntax errors?

Is there any documentation that you are following?
Yes, I have read every documentation about it, but didn't find any solution.

What is the link to your site?
hidden link

The header of the articles is broken, because of the wrong syntax in the condition.

February 13, 2020 at 2:47 pm #1507193

Shane

Supporter

Languages: English (English )

Timezone: America/Jamaica (GMT-05:00)

Hi Peter,

Thank you for getting in touch.

In a case like this you would add it like below.

[wpv-conditional if="( '[wpv-post-taxonomy type='category' format='slug']' ne '' )"]

Please try this and let me know if it helps.
Thanks,
Shane

February 13, 2020 at 6:06 pm #1507579

Peter

My issue is resolved now. Thank you!

This ticket is now closed. If you're a WPML client and need related help, please open a new support ticket.